电解时，发生如下反应2NaCl+2H2O=2NaOH+H2+Cl2PH=13,C(OH)=C(NaOH)=(1*10^-14)/(1*10^-13)=0.1mol/Ln(NaOH)=C(NaOH)*V=0.05mol阴极收集氢气 n(H2)=0.025mol,V(H2)=0.56L
