∫x(e^x-1)dx

2026-05-19 13:04:55
推荐回答(2个)
回答1:

∫x(e∧x-1)dx
=∫xe∧xdx-∫xdx
=∫xde∧x-∫xdx
=xe∧x-∫e∧xdx-∫xdx
=xe∧x-e∧x-x²/2+C
=e∧x(x-1)-x²/2+C

回答2:

3